What is (\partial)/(\partial x)(600-4x+10x^2y) ?

The answer to (\partial)/(\partial x)(600-4x+10x^2y) is 20xy-4

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(\partial)/(\partial x)(600-4x+10x^2y)

\frac{\partial}{\partial x} (600 - 4 x + 10 x^{2} y)

20 x y - 4

Solution steps

\frac{\partial}{\partial x} (600 - 4 x + 10 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (600) - \frac{\partial}{\partial x} (4 x) + \frac{\partial}{\partial x} (10 x^{2} y)

\frac{\partial}{\partial x} (600) = 0

\frac{\partial}{\partial x} (4 x) = 4

\frac{\partial}{\partial x} (10 x^{2} y) = 20 y x

= 0 - 4 + 20 y x

Simplify

= 20 x y - 4

d er i v a t i v e f (x) = \frac{x ^{2} - 5 x + 4}{x ^{2} + 5 x + 4}

t an g e n t y = x + 5, (4, 3)

\int (- \frac{2000}{x ^{2}}) d x

\frac{d}{d x} (ln (h (x^{2})))

\int t sin (7 t) d t

What is (\partial)/(\partial x)(600-4x+10x^2y) ?
The answer to (\partial)/(\partial x)(600-4x+10x^2y) is 20xy-4