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tangent f(x)=-3x^3-2x^2-x+3,(-,5)

解答

切线

f (x) = - 3 x^{3} - 2 x^{2} - x + 3, (-, 5)

解答

y = - 6.61329 \dots x + 11.61329 \dots

求解步骤

(-, 5)

处的切线斜率:

m = \frac{- 3 x ^{3} - 2 x ^{2} - x - 2}{x}

计算

f (x) = - 3 x^{3} - 2 x^{2} - x + 3

的斜率:

m = - 9 x^{2} - 4 x - 1

解

- 9 x^{2} - 4 x - 1 = \frac{- 3 x ^{3} - 2 x ^{2} - x - 2}{x} : x \approx 0.59819 \dots

求出

x = 0.59819 \dots

处的切线:

y = - 6.61329 \dots x + 11.61329 \dots

y = - 6.61329 \dots x + 11.61329 \dots

作图

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