What is (\partial)/(\partial x)(m/p+625 p/x) ?

The answer to (\partial)/(\partial x)(m/p+625 p/x) is -(625p)/(x^2)

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(\partial)/(\partial x)(m/p+625 p/x)

\frac{\partial}{\partial x} (\frac{m}{p} + 625 \frac{p}{x})

- \frac{625 p}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{m}{p} + 625 \cdot \frac{p}{x})

Simplify

\frac{m}{p} + 625 \cdot \frac{p}{x} : \frac{m}{p} + \frac{625 p}{x}

= \frac{\partial}{\partial x} (\frac{m}{p} + \frac{625 p}{x})

Treat

p, m

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{m}{p}) + \frac{\partial}{\partial x} (\frac{625 p}{x})

\frac{\partial}{\partial x} (\frac{m}{p}) = 0

\frac{\partial}{\partial x} (\frac{625 p}{x}) = - \frac{625 p}{x ^{2}}

= 0 - \frac{625 p}{x ^{2}}

Simplify

= - \frac{625 p}{x ^{2}}

\frac{d}{d x} (e^{\frac{3 x ^{2}}{2}})

\frac{\partial}{\partial x} (\frac{m c T}{wp ( m , T , w , x )})

\int_{0}^{π} π^{25} sin^{2} (x) d x

\int 1 d θ

\int_{0}^{9} 1 + x d x

What is (\partial)/(\partial x)(m/p+625 p/x) ?
The answer to (\partial)/(\partial x)(m/p+625 p/x) is -(625p)/(x^2)