en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=ysin(x),y(0)=1

Solution

y^{^{'}} = y sin (x), y (0) = 1

Solution

y = e^{- c o s (x) + 1}

Solution steps

y^{'} (x) = y sin (x)

Solve separable ODE:

y = e^{- c o s (x) + 1}

y = e^{- c o s (x) + 1}

Popular Examples

1/6 y^{''}+6y=tan(6t)-1/2 e^{3t}

\frac{1}{6} y^{^{''}} + 6 y = tan (6 t) - \frac{1}{2} e^{3 t}

(\partial)/(\partial x)(tan(y))

\frac{\partial}{\partial x} (tan (y))

(dy)/(dx)=((2880-y))/(320)

\frac{d y}{d x} = \frac{( 2880 - y )}{320}

y^{^{'}} + y = 1, y (0) = 1

integral of (x^3+1)

\int (x^{3} + 1) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=ysin(x),y(0)=1 ?
The solution for y^'=ysin(x),y(0)=1 is y=e^{-cos(x)+1}