What is the d/(dt)(tan(e^{2t})+e^{tan(2t)}) ?

The d/(dt)(tan(e^{2t})+e^{tan(2t)}) is sec^2(e^{2t})e^{2t}*2+e^{tan(2t)}sec^2(2t)*2

What is the first d/(dt)(tan(e^{2t})+e^{tan(2t)}) ?

The first d/(dt)(tan(e^{2t})+e^{tan(2t)}) is sec^2(e^{2t})e^{2t}*2+e^{tan(2t)}sec^2(2t)*2

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\frac{d}{d t} (tan (e^{2 t}) + e^{t a n (2 t)})

sec^{2} (e^{2 t}) e^{2 t} \cdot 2 + e^{t a n (2 t)} sec^{2} (2 t) \cdot 2

Solution steps

\frac{d}{d t} (tan (e^{2 t}) + e^{t a n (2 t)})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (e^{2 t})) + \frac{d}{d t} (e^{t a n (2 t)})

\frac{d}{d t} (tan (e^{2 t})) = sec^{2} (e^{2 t}) e^{2 t} \cdot 2

\frac{d}{d t} (e^{t a n (2 t)}) = e^{t a n (2 t)} sec^{2} (2 t) \cdot 2

= sec^{2} (e^{2 t}) e^{2 t} \cdot 2 + e^{t a n (2 t)} sec^{2} (2 t) \cdot 2

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\frac{d}{d x} (x^{3} - 2 x^{2} + x + 1)

\frac{\partial}{\partial x} (\frac{e ^{x}}{y + x ^{3}})

\frac{d}{d x} (tan (\frac{π}{4}))

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What is the d/(dt)(tan(e^{2t})+e^{tan(2t)}) ?
The d/(dt)(tan(e^{2t})+e^{tan(2t)}) is sec^2(e^{2t})e^{2t}*2+e^{tan(2t)}sec^2(2t)*2
What is the first d/(dt)(tan(e^{2t})+e^{tan(2t)}) ?
The first d/(dt)(tan(e^{2t})+e^{tan(2t)}) is sec^2(e^{2t})e^{2t}*2+e^{tan(2t)}sec^2(2t)*2