What is the d/(dt)(Ce^{3t}-e^2) ?

The d/(dt)(Ce^{3t}-e^2) is 3e^{3t}C

What is the first d/(dt)(Ce^{3t}-e^2) ?

The first d/(dt)(Ce^{3t}-e^2) is 3e^{3t}C

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\frac{d}{d t} (C e^{3 t} - e^{2})

3 e^{3 t} C

Solution steps

\frac{d}{d t} (C e^{3 t} - e^{2})

Treat

C

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (C e^{3 t}) - \frac{d}{d t} (e^{2})

\frac{d}{d t} (C e^{3 t}) = C e^{3 t} \cdot 3

\frac{d}{d t} (e^{2}) = 0

= C e^{3 t} \cdot 3 - 0

Simplify

= 3 e^{3 t} C

x \to 0 lim (- \frac{1}{2 ( 2 + x )})

n = 1 \sum \infty (- 1)^{n} n! x^{n}

\frac{1}{2 t + 4 i} + 2 j

\int_{0}^{1} arctan (4 x) d x

\int \frac{3}{( x ^{2} + 2 ) ^{2}} d x

What is the d/(dt)(Ce^{3t}-e^2) ?
The d/(dt)(Ce^{3t}-e^2) is 3e^{3t}C
What is the first d/(dt)(Ce^{3t}-e^2) ?
The first d/(dt)(Ce^{3t}-e^2) is 3e^{3t}C