What is the solution for (dy)/(dt)=-3/(4sqrt(t)) ?

The solution for (dy)/(dt)=-3/(4sqrt(t)) is y=-3/2 sqrt(t)+c_{1}

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(dy)/(dt)=-3/(4sqrt(t))

\frac{d y}{d t} = - \frac{3}{4 t}

y = - \frac{3}{2} t + c_{1}

Solution steps

\frac{d y}{d t} = - \frac{3}{4 t}

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = - \frac{3}{4 t}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - \frac{3}{4 t} d t

\int - \frac{3}{4 t} d t = - \frac{3}{2} t + c_{1}

y = - \frac{3}{2} t + c_{1}

\frac{\partial}{\partial x} (- \frac{2 x}{3 y})

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (2) = 1

\int_{1}^{\infty} e^{- s t} d t

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

x (\frac{d y}{d x}) = \frac{( 1 - 4 y ^{2} )}{3 y}

What is the solution for (dy)/(dt)=-3/(4sqrt(t)) ?
The solution for (dy)/(dt)=-3/(4sqrt(t)) is y=-3/2 sqrt(t)+c_{1}