What is the sum from n=0 to infinity of n/(3n+1) ?

The sum from n=0 to infinity of n/(3n+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of n/(3n+1)

n = 0 \sum \infty \frac{n}{3 n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{3 n + 1}

Apply Series Divergence Test:

diverges

= diverges

x \to 5 - lim (ln (5 - x))

x \to 0 lim (3 x^{n} \cdot sin (\frac{2}{x}))

\frac{d y}{d x} = 5 e^{x - y}

\int \frac{7}{x ^{2} - 12 x + 34} d x

(- 4, 3), (- 2, 1)

What is the sum from n=0 to infinity of n/(3n+1) ?
The sum from n=0 to infinity of n/(3n+1) is diverges