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tangent f(x)=(5x)/(x+3),2,\at x=2

解答

切线

f (x) = \frac{5 x}{x + 3}, 2, at x = 2

解答

y = \frac{3}{5} x + \frac{4}{5}

求解步骤

找到切点:

(2, 2)

计算

f (x) = \frac{5 x}{x + 3}

的斜率:

\frac{df ( x )}{d x} = \frac{15}{( x + 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{5}

找到斜率 m=

\frac{3}{5}

且穿过

(2, 2)

的直线:

y = \frac{3}{5} x + \frac{4}{5}

y = \frac{3}{5} x + \frac{4}{5}

作图

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