What is the derivative of f(x)=arctan(x)+arctan(1/x) ?

The derivative of f(x)=arctan(x)+arctan(1/x) is 0

What is the first derivative of f(x)=arctan(x)+arctan(1/x) ?

The first derivative of f(x)=arctan(x)+arctan(1/x) is 0

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derivative of

f (x) = arctan (x) + arctan (\frac{1}{x})

0

Solution steps

\frac{d}{d x} (arctan (x) + arctan (\frac{1}{x}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arctan (x)) + \frac{d}{d x} (arctan (\frac{1}{x}))

\frac{d}{d x} (arctan (x)) = \frac{1}{x ^{2} + 1}

\frac{d}{d x} (arctan (\frac{1}{x})) = - \frac{1}{1 + x ^{2}}

= \frac{1}{x ^{2} + 1} - \frac{1}{1 + x ^{2}}

Simplify

\frac{1}{x ^{2} + 1} - \frac{1}{1 + x ^{2}} : 0

= 0

f (x) = ln (sin (x))

\frac{12}{t}

x \to 0 + lim ((tan (9 x))^{x})

\int \frac{1}{x ^{3} - 4 x} d x

\int \frac{3 x ^{2} + 1}{( x ^{2} - 1 ) ^{3}} d x

What is the derivative of f(x)=arctan(x)+arctan(1/x) ?
The derivative of f(x)=arctan(x)+arctan(1/x) is 0
What is the first derivative of f(x)=arctan(x)+arctan(1/x) ?
The first derivative of f(x)=arctan(x)+arctan(1/x) is 0