What is the integral from 6 to 7 of 1/20+x/(40) ?

The integral from 6 to 7 of 1/20+x/(40) is 17/80

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 6 to 7 of 1/20+x/(40)

\int_{6}^{7} \frac{1}{20} + \frac{x}{40} d x

\frac{17}{80}

Decimal

0.2125

Solution steps

\int_{6}^{7} \frac{1}{20} + \frac{x}{40} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6}^{7} \frac{1}{20} d x + \int_{6}^{7} \frac{x}{40} d x

\int_{6}^{7} \frac{1}{20} d x = \frac{1}{20}

\int_{6}^{7} \frac{x}{40} d x = \frac{13}{80}

= \frac{1}{20} + \frac{13}{80}

Simplify

\frac{1}{20} + \frac{13}{80} : \frac{17}{80}

= \frac{17}{80}

\int \frac{1}{2 + 9 x} d x

x \to 0 lim (2 x \cdot cot (3 x))

\frac{d ^{3}}{d x ^{3}} (4 t + 8)

\int \frac{5}{x ^{2} + 4 x + 13} d x

\frac{d}{d x} (e^{4 x} ln (y))

What is the integral from 6 to 7 of 1/20+x/(40) ?
The integral from 6 to 7 of 1/20+x/(40) is 17/80