What is the integral of-4/x ?

The integral of-4/x is -4ln|x|+C

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integral of-4/x

\int - \frac{4}{x} d x

- 4 ln ∣ x ∣ + C

Solution steps

\int - \frac{4}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= - 4 ln ∣ x ∣

Add a constant to the solution

= - 4 ln ∣ x ∣ + C

(x - 2) (x^{2} + 4)

6 cos (x)

- \frac{2}{9 ( 1 + x ) ^{\frac{5}{3}}}

\frac{d}{d x} (tan (\frac{π x}{2}))

y = 3 + \frac{12}{2 - x}