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Popular >

area 2x^2-x^3,y=0

Solution

area

2 x^{2} - x^{3}, y = 0

Solution

\frac{4}{3}

+1

Decimal Notation

1.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} - x^{3} + 2 x^{2} d x

Solve

\int_{0}^{2} - x^{3} + 2 x^{2} d x : \frac{4}{3}

The area is:

= \frac{4}{3}

Popular Examples

integral of-3/2 x^2

\int - \frac{3}{2} x^{2} d x

integral of (tan(x/(18)))^5

\int (tan (\frac{x}{18}))^{5} d x

derivative of (4x/((1-x^2)^2))

\frac{d}{d x} (\frac{4 x}{( 1 - x ^{2} ) ^{2}})

tangent of f(x)=x^2+3x+2,\at x=1 tangent of

f (x) = x^{2} + 3 x + 2, at x = 1

laplacetransform e^{-2t}cos(2t)laplace transform

e^{- 2 t} cos (2 t)

Frequently Asked Questions (FAQ)

What is area 2x^2-x^3,y=0 ?
The answer to area 2x^2-x^3,y=0 is 4/3