What is the integral from 0 to 2pi of sin(x) ?

The integral from 0 to 2pi of sin(x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of sin(x)

\int_{0}^{2 π} sin (x) d x

0

Solution steps

\int_{0}^{2 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{2 π}

Compute the boundaries:

0

= 0

\int 3 sin (3 x) + 2 cos (4 x) d x

y^{^{'''}} + 2 y^{^{''}} - y^{^{'}} - 2 y = sin (3 t)

\frac{3 x}{x}

\int - x^{3} - 8 x + 5 d x

x \to 0 lim (\frac{1}{x + x ^{5}})

What is the integral from 0 to 2pi of sin(x) ?
The integral from 0 to 2pi of sin(x) is 0