derivative-4x^2+1

Lösung

ableitung von

- 4 x^{2} + 1

- 8 x

Schritte zur Lösung

\frac{d}{d x} (- 4 x^{2} + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (1) = 0

= - 8 x + 0

Vereinfache

= - 8 x

\frac{\partial}{\partial y} (sin (x^{5} - 7 y))

\frac{d y}{d x} = (\frac{4}{x ^{2} + 1}) (y + 1)

y^{^{''}} + 4 y = e^{x}

\int \frac{1}{x ^{2} x ^{2} - 1} d x

d er i v a t i v e f (x) = cos (8 x^{2} - 16) sin (x^{2})