What is the solution for (3x^2y^2)dx+(2x^3y+4y^3)dy=0 ?

The solution for (3x^2y^2)dx+(2x^3y+4y^3)dy=0 is

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(3x^2y^2)dx+(2x^3y+4y^3)dy=0

(3 x^{2} y^{2}) d x + (2 x^{3} y + 4 y^{3}) d y = 0

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

Solution steps

(3 x^{2} y^{2}) d x + (2 x^{3} y + 4 y^{3}) d y = 0

Solve exact ODE:

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

y = \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} + x ^{6} + c _{1}}{2}, y = \frac{- x ^{3} - x ^{6} + c _{1}}{2}, y = - \frac{- x ^{3} - x ^{6} + c _{1}}{2}

x \to - \frac{π}{3} lim (- 2 cos (x))

\frac{d}{d x} (sin (x^{2}) + cos^{2} (x))

\frac{\partial}{\partial x} (\frac{2}{2 x - y})

\int_{1}^{\infty} \frac{1}{x ^{2} + 5} d x

5^{t}

What is the solution for (3x^2y^2)dx+(2x^3y+4y^3)dy=0 ?
The solution for (3x^2y^2)dx+(2x^3y+4y^3)dy=0 is