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Popular >

y^'=7x+y,y(0)=8

Solution

y^{^{'}} = 7 x + y, y (0) = 8

Solution

y = - 7 (x + 1) + 15 e^{x}

Solution steps

y^{'} (x) = 7 x + y

Solve linear ODE:

y = - 7 (x + 1) + 15 e^{x}

y = - 7 (x + 1) + 15 e^{x}

Popular Examples

area y=x^3,y=3x+2 area

y = x^{3}, y = 3 x + 2

(\partial)/(\partial x)(2xy+y^3)

\frac{\partial}{\partial x} (2 x y + y^{3})

integral from 0 to 1 of 1/(t+1)

\int_{0}^{1} \frac{1}{t + 1} d t

implicit (dy)/(dx),xy=36 implicit derivative

\frac{d y}{d x}, x y = 36

(dy)/(dt)+2ty=2t

\frac{d y}{d t} + 2 t y = 2 t

Frequently Asked Questions (FAQ)

What is the solution for y^'=7x+y,y(0)=8 ?
The solution for y^'=7x+y,y(0)=8 is y=-7(x+1)+15e^x