What is (\partial)/(\partial y)(5x^2-2y) ?

The answer to (\partial)/(\partial y)(5x^2-2y) is -2

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(\partial)/(\partial y)(5x^2-2y)

\frac{\partial}{\partial y} (5 x^{2} - 2 y)

- 2

Solution steps

\frac{\partial}{\partial y} (5 x^{2} - 2 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (5 x^{2}) - \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (5 x^{2}) = 0

\frac{\partial}{\partial y} (2 y) = 2

= 0 - 2

Simplify

= - 2

\frac{1}{( s ^{2} + 9 ) ^{2}}

n = 1 \sum \infty \frac{9}{n ln ( 2 n )}

\frac{\partial}{\partial y} (4 y sin (x^{2} y))

\int_{2}^{9} \frac{2}{( 1 - x ) ^{\frac{2}{3}}} d x

\int_{0}^{5} 2 d x

What is (\partial)/(\partial y)(5x^2-2y) ?
The answer to (\partial)/(\partial y)(5x^2-2y) is -2