d/(dθ)(sqrt(1+cos(2θ)))

Lösung

\frac{d}{d θ} (1 + cos (2 θ))

- \frac{sin ( 2 θ )}{2 cos ( θ )}

Schritte zur Lösung

\frac{d}{d θ} (1 + cos (2 θ))

Wende die Kettenregel an:

\frac{1}{2 1 + cos ( 2 θ )} \frac{d}{d θ} (1 + cos (2 θ))

= \frac{1}{2 1 + cos ( 2 θ )} \frac{d}{d θ} (1 + cos (2 θ))

\frac{d}{d θ} (1 + cos (2 θ)) = - 2 sin (2 θ)

= \frac{1}{2 1 + cos ( 2 θ )} (- 2 sin (2 θ))

Vereinfache

\frac{1}{2 1 + cos ( 2 θ )} (- 2 sin (2 θ)) : - \frac{sin ( 2 θ )}{2 cos ( θ )}

= - \frac{sin ( 2 θ )}{2 cos ( θ )}

a re a x^{2}, 6 - x, [- 3, 2]

t an g e n t y = 4 x, (1, 1)

d er i v a t i v e f (x) = \frac{4 x}{( x ^{3} - 6 ) ^{2}}

y^{^{''}} + 3 y^{^{'}} + y = 1, y (0) = 1, y^{^{'}} (0) = 0

x \to 0 lim (c e^{x} + 1)