What is the integral from 0 to 6 of xe^{-x} ?

The integral from 0 to 6 of xe^{-x} is -7/(e^6)+1

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integral from 0 to 6 of xe^{-x}

\int_{0}^{6} x e^{- x} d x

- \frac{7}{e ^{6}} + 1

Decimal Notation

0.98264 \dots

Solution steps

\int_{0}^{6} x e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x - \int - e^{- x} d x]_{0}^{6}

= [- e^{- x} x - \int - e^{- x} d x]_{0}^{6}

\int - e^{- x} d x = e^{- x}

= [- e^{- x} x - e^{- x}]_{0}^{6}

Compute the boundaries:

- \frac{7}{e ^{6}} + 1

= - \frac{7}{e ^{6}} + 1

\frac{d}{d x} (\frac{( 5 x ^{4} + x ^{2} )}{2})

(1 + x^{2}) (1 + y^{2}) d x - x y d y = 0

\int (6 sin (3 x) - cos (2 x)) d x

\int x - 4 d x

What is the integral from 0 to 6 of xe^{-x} ?
The integral from 0 to 6 of xe^{-x} is -7/(e^6)+1