What is the derivative of-6.25t^2+50t ?

The derivative of-6.25t^2+50t is -12.5t+50

What is the first derivative of-6.25t^2+50t ?

The first derivative of-6.25t^2+50t is -12.5t+50

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derivative of

- 6.25 t^{2} + 50 t

- 12.5 t + 50

Solution steps

\frac{d}{d t} (- 6.25 t^{2} + 50 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (6.25 t^{2}) + \frac{d}{d t} (50 t)

\frac{d}{d t} (6.25 t^{2}) = 12.5 t

\frac{d}{d t} (50 t) = 50

= - 12.5 t + 50

(x^{2} + 4 x y) d x + x d y = 0

x \to 1 lim (\frac{5}{( x - 1 ) ^{2}})

\frac{d}{d x} ((1 + 2 x + 3 x^{2} + 4 x^{3})^{100})

\frac{10}{( s - 2 ) ( s ^{3} + s )}

2 t y^{^{'}} = 4 y

What is the derivative of-6.25t^2+50t ?
The derivative of-6.25t^2+50t is -12.5t+50
What is the first derivative of-6.25t^2+50t ?
The first derivative of-6.25t^2+50t is -12.5t+50