What is the integral of 1/(10sqrt(x)) ?

The integral of 1/(10sqrt(x)) is 1/5 sqrt(x)+C

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integral of 1/(10sqrt(x))

\int \frac{1}{10 x} d x

\frac{1}{5} x + C

Solution steps

\int \frac{1}{10 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{10} \cdot \int \frac{1}{x} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= \frac{1}{10} \cdot 2 x^{\frac{1}{2}}

Simplify

\frac{1}{10} \cdot 2 x^{\frac{1}{2}} : \frac{1}{5} x

= \frac{1}{5} x

Add a constant to the solution

= \frac{1}{5} x + C

\frac{\partial}{\partial x} (\frac{8 y}{9 x ^{2} + 4 y ^{2} + 5})

\frac{d y}{d x} = - sin^{2} (y)

n = 1 \sum \infty (- 1)^{n} (- 1)^{n}

\frac{d}{d x} (5 x^{l n (x)})

\frac{d y}{d x} y = x^{x}

What is the integral of 1/(10sqrt(x)) ?
The integral of 1/(10sqrt(x)) is 1/5 sqrt(x)+C