What is the limit as x approaches 0+of ((ln(x))^2)/x ?

The limit as x approaches 0+of ((ln(x))^2)/x is infinity

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limit as x approaches 0+of ((ln(x))^2)/x

x \to 0 + lim (\frac{( ln ( x ) ) ^{2}}{x})

\infty

Solution steps

x \to 0 + lim (\frac{( ln ( x ) ) ^{2}}{x})

\frac{ln ^{2} ( x )}{x} = ln^{2} (x) \frac{1}{x}

= x \to 0 + lim (ln^{2} (x) \frac{1}{x})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (ln^{2} (x)) \cdot x \to 0 + lim (\frac{1}{x})

x \to 0 + lim (ln^{2} (x)) = \infty

x \to 0 + lim (\frac{1}{x}) = \infty

= \infty \cdot \infty

Apply Infinity Property:

\infty \infty = \infty

= \infty

\frac{\partial}{\partial x} (sin^{4} (x))

(- 4, 6), (3, - 8)

\int (4 x^{3} - 2) x^{2} d x

n = 1 \sum \infty \frac{n !}{5 ^{n}}

f (x) = \frac{1}{x ^{16}}

What is the limit as x approaches 0+of ((ln(x))^2)/x ?
The limit as x approaches 0+of ((ln(x))^2)/x is infinity