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Popular >

y^'=2x+4y

Solution

y^{^{'}} = 2 x + 4 y

Solution

y = - \frac{4 x + 1}{8} + c_{1} e^{4 x}

Solution steps

y^{'} (x) = 2 x + 4 y

Solve linear ODE:

y = - \frac{4 x + 1}{8} + c_{1} e^{4 x}

y = - \frac{4 x + 1}{8} + c_{1} e^{4 x}

Popular Examples

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\int \frac{x}{2 + 3 x} d x

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\int \frac{x}{1 - x} d x

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\int_{- 1}^{0} 2 x - e^{x} d x

derivative of t/4 derivative of

\frac{t}{4}

derivative of 5(x^2+7^4(2x))

\frac{d}{d x} (5 (x^{2} + 7)^{4} (2 x))

Frequently Asked Questions (FAQ)

What is the solution for y^'=2x+4y ?
The solution for y^'=2x+4y is y=-(4x+1)/8+c_{1}e^{4x}