y^{''}+25y=-40sec(5t)

Lösung

y^{^{''}} + 25 y = - 40 sec (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) - \frac{8}{5} ln (cos (5 t)) cos (5 t) - 8 t sin (5 t)

Schritte zur Lösung

y^{''} (t) + 25 y = - 40 sec (5 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) - \frac{8}{5} ln (cos (5 t)) cos (5 t) - 8 t sin (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) - \frac{8}{5} ln (cos (5 t)) cos (5 t) - 8 t sin (5 t)

\int \frac{1}{a ^{2} - x ^{2}} d x

x \to 2 lim ((x^{2})^{2})

a re a y = x, y = 3 x, y = - x + 2

n = 0 \sum \infty n \cdot (\frac{3}{4})^{n}

\int \frac{( x + 1 )}{x ^{3} + x ^{2} + 6 x} d x