integral of (6x+2)/(x^2+9)

Lösung

\int \frac{6 x + 2}{x ^{2} + 9} d x

3 ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3}) + C

Schritte zur Lösung

\int \frac{6 x + 2}{x ^{2} + 9} d x

Multipliziere aus

\frac{6 x + 2}{x ^{2} + 9} : \frac{6 x}{x ^{2} + 9} + \frac{2}{x ^{2} + 9}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6 x}{x ^{2} + 9} d x + \int \frac{2}{x ^{2} + 9} d x

\int \frac{6 x}{x ^{2} + 9} d x = 3 ln x^{2} + 9

\int \frac{2}{x ^{2} + 9} d x = \frac{2}{3} arctan (\frac{x}{3})

= 3 ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3})

Füge eine Konstante zur Lösung hinzu

= 3 ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3}) + C

\frac{d}{d x} (\frac{x + 3}{x + 2})

\frac{d}{d x} (\frac{4}{4 - 10 x})

\frac{d}{d x} (\frac{x ^{2} - 2}{x})

t an g e n t x^{2} + 2 x y - y^{2} + x = 5, (3, 7)

\frac{d}{d t} (t ln (t))