derivative of arcsin(x+1)

Lösung

\frac{d}{d x} (arcsin (x + 1))

\frac{1}{- x ^{2} - 2 x}

Schritte zur Lösung

\frac{d}{d x} (arcsin (x + 1))

Wende die Kettenregel an:

\frac{1}{1 - ( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= \frac{1}{1 - ( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{1 - ( x + 1 ) ^{2}} \cdot 1

Vereinfache

\frac{1}{1 - ( x + 1 ) ^{2}} \cdot 1 : \frac{1}{- x ^{2} - 2 x}

= \frac{1}{- x ^{2} - 2 x}

\int_{2}^{x^{2}} cos (x^{2} + 1) d x

\int_{0}^{2 π} x^{2} sin (2 x) d x

\frac{d}{d t} (3 sin (3 t))

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\frac{\partial}{\partial x} (\frac{26 x ^{2}}{( x - y ) ^{2}})