What is the solution for 5x^2y^'=y^'+6xe^{-y} ?

The solution for 5x^2y^'=y^'+6xe^{-y} is y=ln(3/5 ln(5x^2-1)+c_{1})

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5x^2y^'=y^'+6xe^{-y}

5 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

Solution steps

5 x^{2} y^{'} (x) = y^{'} (x) + 6 x e^{- y}

Solve separable ODE:

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

y = ln (\frac{3}{5} ln (5 x^{2} - 1) + c_{1})

\frac{\partial}{\partial x} ((x^{2} + y^{2} + z^{2})^{- \frac{1}{4}})

x \to 0 lim (\frac{x - 2}{x})

\frac{\partial}{\partial y} (- 8 y^{3} + 4 x y + 4 x^{2} + 9 y^{2})

\int_{1}^{n} \frac{1}{x ^{1.1}} d x

\frac{\partial}{\partial x} (\frac{x}{10} cos (5 x))

What is the solution for 5x^2y^'=y^'+6xe^{-y} ?
The solution for 5x^2y^'=y^'+6xe^{-y} is y=ln(3/5 ln(5x^2-1)+c_{1})