d/(dθ)(sin^2(θ/2))

Lösung

\frac{d}{d θ} (sin^{2} (\frac{θ}{2}))

\frac{sin ( θ )}{2}

Schritte zur Lösung

\frac{d}{d θ} (sin^{2} (\frac{θ}{2}))

Wende die Kettenregel an:

2 sin (\frac{θ}{2}) \frac{d}{d θ} (sin (\frac{θ}{2}))

= 2 sin (\frac{θ}{2}) \frac{d}{d θ} (sin (\frac{θ}{2}))

\frac{d}{d θ} (sin (\frac{θ}{2})) = cos (\frac{θ}{2}) \frac{1}{2}

= 2 sin (\frac{θ}{2}) cos (\frac{θ}{2}) \frac{1}{2}

Vereinfache

2 sin (\frac{θ}{2}) cos (\frac{θ}{2}) \frac{1}{2} : \frac{sin ( θ )}{2}

= \frac{sin ( θ )}{2}

t an g e n t f (x) = x^{2} (2 x + \frac{1}{x}), at x = 3

\int 7 x - x d x

d er i v a t i v e y = ln (- 3 x^{6})

(1 + y^{2}) d x - (x^{2} + 1) d y = 0

\frac{\partial}{\partial x} (\frac{- y ^{4}}{4 x ^{4}})