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Popular >

y^'=(y^2-y)/x

Solution

y^{^{'}} = \frac{y ^{2} - y}{x}

Solution

y = \frac{1}{1 - c _{1} x}

Solution steps

y^{'} (x) = \frac{y ^{2} - y}{x}

Solve separable ODE:

y = \frac{1}{1 - c _{1} x}

y = \frac{1}{1 - c _{1} x}

Popular Examples

area x+2,x^2,-1,2 area

x + 2, x^{2}, - 1, 2

derivative of y=(sqrt(x))/(3+x)derivative of

y = \frac{x}{3 + x}

integral of-3/(x^3)

\int - \frac{3}{x ^{3}} d x

derivative of arcsin(x^2-3)

\frac{d}{d x} (arcsin (x^{2} - 3))

integral of 2/((1-x^2)^{3/2)}

\int \frac{2}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(y^2-y)/x ?
The solution for y^'=(y^2-y)/x is y= 1/(1-c_{1)x}