integral from-1 to 1 of ln|x|

解答

\int_{- 1}^{1} ln ∣ x ∣ d x

- 2

求解步骤

\int_{- 1}^{1} ln ∣ x ∣ d x

拿掉绝对值

= \int_{- 1}^{0} ln (- x) d x + \int_{0}^{1} ln (x) d x

\int_{- 1}^{0} ln (- x) d x = - 1

\int_{0}^{1} ln (x) d x = - 1

= - 1 - 1

化简

= - 2

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