What is the derivative of (pi-2x^2) ?

The derivative of (pi-2x^2) is -4(pi-2x)

What is the first derivative of (pi-2x^2) ?

The first derivative of (pi-2x^2) is -4(pi-2x)

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\frac{d}{d x} ((π - 2 x)^{2})

- 4 (π - 2 x)

Solution steps

\frac{d}{d x} ((π - 2 x)^{2})

Apply the chain rule:

2 (π - 2 x) \frac{d}{d x} (π - 2 x)

= 2 (π - 2 x) \frac{d}{d x} (π - 2 x)

\frac{d}{d x} (π - 2 x) = - 2

= 2 (π - 2 x) (- 2)

Simplify

= - 4 (π - 2 x)

\int \frac{1}{t ^{2} - 12 t + 45} d t

(1 + x) e^{- x}

\frac{e ^{x} - e ^{- x}}{2}

\frac{d}{d x} ((x)^{\frac{1}{3}})

\frac{d}{d x} (- \frac{ln ( 1 + 6 x )}{x})

What is the derivative of (pi-2x^2) ?
The derivative of (pi-2x^2) is -4(pi-2x)
What is the first derivative of (pi-2x^2) ?
The first derivative of (pi-2x^2) is -4(pi-2x)