What is the derivative of f(x)=3x-4 ?

The derivative of f(x)=3x-4 is 3

What is the first derivative of f(x)=3x-4 ?

The first derivative of f(x)=3x-4 is 3

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derivative of

f (x) = 3 x - 4

3

Solution steps

\frac{d}{d x} (3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 3 - 0

Simplify

= 3

\int_{- \infty}^{1} e^{4 x} d x

\frac{d}{d x} (\frac{x ^{2} - 2 x - 3}{( x - 1 ) ^{2}})

n = 2 \sum \infty \frac{9}{n ( n + 2 )}

\frac{d}{d x} (\frac{x}{1 + x ^{2} + x ^{4}})

\frac{d}{d x} (- 7 x^{3} - \frac{2}{x ^{3}} + 7 x)

What is the derivative of f(x)=3x-4 ?
The derivative of f(x)=3x-4 is 3
What is the first derivative of f(x)=3x-4 ?
The first derivative of f(x)=3x-4 is 3