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Popular >

y^'=-3y^2

Solution

y^{^{'}} = - 3 y^{2}

Solution

y = - \frac{1}{- 3 t + c _{1}}

Solution steps

y^{'} (t) = - 3 y^{2}

Solve separable ODE:

y = - \frac{1}{- 3 t + c _{1}}

y = - \frac{1}{- 3 t + c _{1}}

Popular Examples

derivative of 1/12 (x+3^3+(x+3)^{-1})

\frac{d}{d x} (\frac{1}{12} (x + 3)^{3} + (x + 3)^{- 1})

integral from 1 to 4 of sqrt(t)ln(t/2)

\int_{1}^{4} t ln (\frac{t}{2}) d t

integral of (4x)/(sqrt(1-16x^4))

\int \frac{4 x}{1 - 16 x ^{4}} d x

normal of y= x/a+a/x ,\at x= a/2 normal of

y = \frac{x}{a} + \frac{a}{x}, at x = \frac{a}{2}

limit as x approaches 5 of [x]

x \to 5 lim ([x])

Frequently Asked Questions (FAQ)

What is the solution for y^'=-3y^2 ?
The solution for y^'=-3y^2 is y=-1/(-3t+c_{1)}