What is the derivative of x^3-8x^2 ?

The derivative of x^3-8x^2 is 3x^2-16x

What is the first derivative of x^3-8x^2 ?

The first derivative of x^3-8x^2 is 3x^2-16x

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derivative of

x^{3} - 8 x^{2}

3 x^{2} - 16 x

Solution steps

\frac{d}{d x} (x^{3} - 8 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (8 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (8 x^{2}) = 16 x

= 3 x^{2} - 16 x

\int_{- 1}^{1} (1 - x^{2}) d x

d er i v a t i v e f (x) = x^{2} x - 5 x

\frac{d}{d x} (3 e^{\frac{x}{4}})

t an g e n t x^{2} - 2 x + 3

\frac{\partial}{\partial u} (v)

What is the derivative of x^3-8x^2 ?
The derivative of x^3-8x^2 is 3x^2-16x
What is the first derivative of x^3-8x^2 ?
The first derivative of x^3-8x^2 is 3x^2-16x