What is the sum from n=0 to infinity of (3^n)/(n^3) ?

The sum from n=0 to infinity of (3^n)/(n^3) is diverges

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sum from n=0 to infinity of (3^n)/(n^3)

n = 0 \sum \infty \frac{3 ^{n}}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty \frac{3 ^{n}}{n ^{3}}

Apply Series Ratio Test:

diverges

= diverges

6 y^{^{'}} = y^{2}

n = 2 \sum \infty \frac{2}{n ^{3} - n}

\frac{d y}{d t} = 0.2 \cdot (y - sin (t)) + cos (t)

\int \frac{1}{3 x + 5} d x

\int (x + 1) (x + 4) d x

What is the sum from n=0 to infinity of (3^n)/(n^3) ?
The sum from n=0 to infinity of (3^n)/(n^3) is diverges