What is the derivative of f(x)=(sin^2(x)+1)^5 ?

The derivative of f(x)=(sin^2(x)+1)^5 is 5(sin^2(x)+1)^4sin(2x)

What is the first derivative of f(x)=(sin^2(x)+1)^5 ?

The first derivative of f(x)=(sin^2(x)+1)^5 is 5(sin^2(x)+1)^4sin(2x)

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derivative of

f (x) = (sin^{2} (x) + 1)^{5}

5 (sin^{2} (x) + 1)^{4} sin (2 x)

Solution steps

\frac{d}{d x} ((sin^{2} (x) + 1)^{5})

Apply the chain rule:

5 (sin^{2} (x) + 1)^{4} \frac{d}{d x} (sin^{2} (x) + 1)

= 5 (sin^{2} (x) + 1)^{4} \frac{d}{d x} (sin^{2} (x) + 1)

\frac{d}{d x} (sin^{2} (x) + 1) = sin (2 x)

= 5 (sin^{2} (x) + 1)^{4} sin (2 x)

\frac{d}{d x} (\frac{- 1 - x}{x - 1})

\int (x^{2} + 5)^{2} d x

x, 25

\int_{1}^{e} x \cdot ln (x) d x

2 sin (x), 4 cos (x)

What is the derivative of f(x)=(sin^2(x)+1)^5 ?
The derivative of f(x)=(sin^2(x)+1)^5 is 5(sin^2(x)+1)^4sin(2x)
What is the first derivative of f(x)=(sin^2(x)+1)^5 ?
The first derivative of f(x)=(sin^2(x)+1)^5 is 5(sin^2(x)+1)^4sin(2x)