What is the integral of (x^{3/2})/x ?

The integral of (x^{3/2})/x is 2/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^{3/2})/x

\int \frac{x ^{\frac{3}{2}}}{x} d x

\frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int \frac{x ^{\frac{3}{2}}}{x} d x

Simplify

\frac{x ^{\frac{3}{2}}}{x} : x^{\frac{1}{2}}

= \int x^{\frac{1}{2}} d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + C

\int e^{- s t} t d t

f (x) = 2 x^{3} - x^{2} + 9, at x = 2

x \to \infty lim (- \frac{π}{2})

x \to 0 lim ((1 - \frac{1}{x})^{x^{2}})

\int \frac{1}{( 49 + x ^{2} ) ^{2}} d x

What is the integral of (x^{3/2})/x ?
The integral of (x^{3/2})/x is 2/3 x^{3/2}+C