What is the solution for (dy)/(dx)+3x^2y=2xe^{-x^3} ?

The solution for (dy)/(dx)+3x^2y=2xe^{-x^3} is y=(x^2)/(e^{x^3)}+(c_{1})/(e^{x^3)}

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(dy)/(dx)+3x^2y=2xe^{-x^3}

\frac{d y}{d x} + 3 x^{2} y = 2 x e^{- x^{3}}

y = \frac{x ^{2}}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

Solution steps

\frac{d y}{d x} + 3 x^{2} y = 2 x e^{- x^{3}}

Solve linear ODE:

y = \frac{x ^{2}}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

y = \frac{x ^{2}}{e ^{x^{3}}} + \frac{c _{1}}{e ^{x^{3}}}

y^{^{'}} + 2 x^{- 1} y = x^{- 1} sin (2 x)

\int_{- 2}^{1} x (4 - x^{2}) - (x + 2) d x

\int \frac{1}{2 ^{x} + 3} d x

n = 1 \sum \infty \frac{1}{n ( n + 5 )}

n = 0 \sum \infty \frac{i ^{n}}{3 ^{n}}

What is the solution for (dy)/(dx)+3x^2y=2xe^{-x^3} ?
The solution for (dy)/(dx)+3x^2y=2xe^{-x^3} is y=(x^2)/(e^{x^3)}+(c_{1})/(e^{x^3)}