y^{''}+10y^'+25y=7e^{2x}

Lösung

y^{^{''}} + 10 y^{^{'}} + 25 y = 7 e^{2 x}

y = c_{1} e^{- 5 x} + c_{2} x e^{- 5 x} + \frac{1}{7} e^{2 x}

Schritte zur Lösung

y^{''} (x) + 10 y^{'} (x) + 25 y = 7 e^{2 x}

Solve linear ODE:

y = c_{1} e^{- 5 x} + c_{2} x e^{- 5 x} + \frac{1}{7} e^{2 x}

y = c_{1} e^{- 5 x} + c_{2} x e^{- 5 x} + \frac{1}{7} e^{2 x}

\int_{- \infty}^{3} x e^{x} d x

t an g e n t 5 e^{x} cos (x) (0.5)

\int x sin (7 x) d x

d er i v a t i v e (1 + cos^{3} (x^{7}))^{12}

\frac{\partial}{\partial x} (y^{3} sin (6 x))