What is (\partial)/(\partial x)(xyz-tan(x+y+z)) ?

The answer to (\partial)/(\partial x)(xyz-tan(x+y+z)) is yz-sec^2(x+y+z)

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(\partial)/(\partial x)(xyz-tan(x+y+z))

\frac{\partial}{\partial x} (x yz - tan (x + y + z))

yz - sec^{2} (x + y + z)

Solution steps

\frac{\partial}{\partial x} (x yz - tan (x + y + z))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x yz) - \frac{\partial}{\partial x} (tan (x + y + z))

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (tan (x + y + z)) = sec^{2} (x + y + z)

= yz - sec^{2} (x + y + z)

n = 1 \sum \infty \frac{2}{n ^{2} - 1}

5 y^{^{''}} + 40 y^{^{'}} + 80 y = 0

x \to 9 lim (5 x + 3)

\int x d x

y^{^{'}} + 2 y = 4 t

What is (\partial)/(\partial x)(xyz-tan(x+y+z)) ?
The answer to (\partial)/(\partial x)(xyz-tan(x+y+z)) is yz-sec^2(x+y+z)