What is the derivative of f(x)=(6x+1)^2 ?

The derivative of f(x)=(6x+1)^2 is 12(6x+1)

What is the first derivative of f(x)=(6x+1)^2 ?

The first derivative of f(x)=(6x+1)^2 is 12(6x+1)

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derivative of

f (x) = (6 x + 1)^{2}

12 (6 x + 1)

Solution steps

\frac{d}{d x} ((6 x + 1)^{2})

Apply the chain rule:

2 (6 x + 1) \frac{d}{d x} (6 x + 1)

= 2 (6 x + 1) \frac{d}{d x} (6 x + 1)

\frac{d}{d x} (6 x + 1) = 6

= 2 (6 x + 1) \cdot 6

Simplify

= 12 (6 x + 1)

\frac{d}{d x} (ln (8 x))

2 \cdot x \cdot y \cdot y^{^{'}} = - (x^{2} + y^{2})

\frac{d}{d x} (\frac{x ^{2}}{( x ^{2} + 5 ) ^{3}})

9 y^{7} + 4 x^{3} = 8 y + 5 x, (1, 1)

\frac{\partial}{\partial x} (cos^{5} (x^{7} y^{5}))

What is the derivative of f(x)=(6x+1)^2 ?
The derivative of f(x)=(6x+1)^2 is 12(6x+1)
What is the first derivative of f(x)=(6x+1)^2 ?
The first derivative of f(x)=(6x+1)^2 is 12(6x+1)