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Popular >

integral from 0 to 7 of 2t^2-20t+48

Solution

\int_{0}^{7} 2 t^{2} - 20 t + 48 d t

Solution

\frac{224}{3}

+1

Decimal Notation

74.66666 \dots

Solution steps

\int_{0}^{7} 2 t^{2} - 20 t + 48 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{7} 2 t^{2} d t - \int_{0}^{7} 20 t d t + \int_{0}^{7} 48 d t

\int_{0}^{7} 2 t^{2} d t = \frac{686}{3}

\int_{0}^{7} 20 t d t = 490

\int_{0}^{7} 48 d t = 336

= \frac{686}{3} - 490 + 336

Simplify

\frac{686}{3} - 490 + 336 : \frac{224}{3}

= \frac{224}{3}

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\int tan^{3} (15 π x) d x

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\int_{1}^{4} \frac{4}{x} - \frac{16}{x ^{2}} d x

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\int cos (\frac{x}{a}) sin (\frac{x}{a}) d x

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\frac{d}{d x} (\frac{2 ^{x}}{1 - x ^{2}})

integral of 1/(x+!)

\int \frac{1}{x + !} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 7 of 2t^2-20t+48 ?
The integral from 0 to 7 of 2t^2-20t+48 is 224/3