What is the derivative of 1-sec(x) ?

The derivative of 1-sec(x) is -sec(x)tan(x)

What is the first derivative of 1-sec(x) ?

The first derivative of 1-sec(x) is -sec(x)tan(x)

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\frac{d}{d x} (1 - sec (x))

- sec (x) tan (x)

Solution steps

\frac{d}{d x} (1 - sec (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (sec (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 0 - sec (x) tan (x)

Simplify

= - sec (x) tan (x)

\int (x^{1.5} + 9 x^{3.5}) d x

(7 x + 2 y) \frac{d y}{d x} = - 2 x - 7 y

x \to 2 + lim (\frac{x + 4}{x - 2})

x \to 0 lim (\frac{7 x}{∣ x ∣})

x \to 1 - lim (ln (x^{2} - 1))

What is the derivative of 1-sec(x) ?
The derivative of 1-sec(x) is -sec(x)tan(x)
What is the first derivative of 1-sec(x) ?
The first derivative of 1-sec(x) is -sec(x)tan(x)