What is the derivative of 1/(8x^2) ?

The derivative of 1/(8x^2) is -1/(4x^3)

What is the first derivative of 1/(8x^2) ?

The first derivative of 1/(8x^2) is -1/(4x^3)

Popular >

derivative of

\frac{1}{8 x ^{2}}

- \frac{1}{4 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{8 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{8} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} (- 2 x^{- 2 - 1})

Simplify

\frac{1}{8} (- 2 x^{- 2 - 1}) : - \frac{1}{4 x ^{3}}

= - \frac{1}{4 x ^{3}}

n = 1 \sum \infty 3^{n}

\int \frac{1 + 2 x}{x} d x

n \to \infty lim (3)

\frac{\partial}{\partial x} (cos (y e^{x y}) sin (x))

\int \frac{( a ^{2} - x ^{2} ) ^{\frac{3}{2}}}{x ^{4}} d x

What is the derivative of 1/(8x^2) ?
The derivative of 1/(8x^2) is -1/(4x^3)
What is the first derivative of 1/(8x^2) ?
The first derivative of 1/(8x^2) is -1/(4x^3)