What is (\partial)/(\partial x)(3x^2+y^3) ?

The answer to (\partial)/(\partial x)(3x^2+y^3) is 6x

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(\partial)/(\partial x)(3x^2+y^3)

\frac{\partial}{\partial x} (3 x^{2} + y^{3})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (y^{3})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (y^{3}) = 0

= 6 x + 0

Simplify

= 6 x

d er i v a t i v e y = x^{\frac{2}{5}}

\frac{d}{d x} (\frac{f ( x , h ) ( x + h ) - f ( x )}{h})

\frac{d}{d n} (i^{n})

x \to 1 lim (\frac{x ^{3}}{3})

d er i v a t i v e f (x) = \frac{x}{5 + x}

What is (\partial)/(\partial x)(3x^2+y^3) ?
The answer to (\partial)/(\partial x)(3x^2+y^3) is 6x