What is the (sin^4(x))^' ?

The (sin^4(x))^' is 4sin^3(x)cos(x)

What is the first (sin^4(x))^' ?

The first (sin^4(x))^' is 4sin^3(x)cos(x)

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(sin^{4} (x))^{^{'}}

4 sin^{3} (x) cos (x)

Solution steps

(sin^{4} (x))^{'}

Apply the chain rule:

4 (sin (x))^{3} (sin (x))^{'}

= 4 (sin (x))^{3} (sin (x))^{'}

(sin (x))^{'} = cos (x)

= 4 (sin (x))^{3} cos (x)

Simplify

= 4 sin^{3} (x) cos (x)

\frac{2}{( s + 1 ) ^{3}}

\frac{d}{d x} (x e^{\frac{y}{x}})

x \to 1 lim ((1 - x)^{2} + 2)

\frac{d}{d x} (\frac{2160}{x ^{2}})

x \to \infty lim (\frac{4}{0})