What is the derivative of sin(x^2-4) ?

The derivative of sin(x^2-4) is cos(x^2-4)*2x

What is the first derivative of sin(x^2-4) ?

The first derivative of sin(x^2-4) is cos(x^2-4)*2x

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\frac{d}{d x} (sin (x^{2} - 4))

cos (x^{2} - 4) \cdot 2 x

Solution steps

\frac{d}{d x} (sin (x^{2} - 4))

Apply the chain rule:

cos (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

= cos (x^{2} - 4) \frac{d}{d x} (x^{2} - 4)

\frac{d}{d x} (x^{2} - 4) = 2 x

= cos (x^{2} - 4) \cdot 2 x

\frac{\partial}{\partial u} ((u^{2} v - v^{3})^{5})

\int x y sin (z) d z

y = x^{- \frac{1}{7}}, (1, 1)

\frac{\partial}{\partial x} (x^{2} + 2 x y + 2 y^{2} - 6 x + 6 y)

\frac{d}{d x} ((x^{2} + 3) (x^{2} - 3) x^{2})

What is the derivative of sin(x^2-4) ?
The derivative of sin(x^2-4) is cos(x^2-4)*2x
What is the first derivative of sin(x^2-4) ?
The first derivative of sin(x^2-4) is cos(x^2-4)*2x