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Beliebt Rechnen >

integral of (4x^2-9x+1)/(x^3-2x^2+x)

Lösung

\int \frac{4 x ^{2} - 9 x + 1}{x ^{3} - 2 x ^{2} + x} d x

Lösung

- \frac{9 x}{x ^{2} - 2 x + 1} + 3 ln ∣ x - 1 ∣ + \frac{13}{x - 1} + \frac{9}{( x - 1 ) ^{2}} + ln ∣ x ∣ + C

Schritte zur Lösung

\int \frac{4 x ^{2} - 9 x + 1}{x ^{3} - 2 x ^{2} + x} d x

Multipliziere aus

\frac{4 x ^{2} - 9 x + 1}{x ^{3} - 2 x ^{2} + x} : \frac{4 x ^{2}}{x ^{3} - 2 x ^{2} + x} - \frac{9 x}{x ^{3} - 2 x ^{2} + x} + \frac{1}{x ^{3} - 2 x ^{2} + x}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4 x ^{2}}{x ^{3} - 2 x ^{2} + x} d x - \int \frac{9 x}{x ^{3} - 2 x ^{2} + x} d x + \int \frac{1}{x ^{3} - 2 x ^{2} + x} d x

\int \frac{4 x ^{2}}{x ^{3} - 2 x ^{2} + x} d x = 4 (ln ∣ x - 1 ∣ - \frac{1}{x - 1})

\int \frac{9 x}{x ^{3} - 2 x ^{2} + x} d x = 9 (\frac{x}{x ^{2} - 2 x + 1} - \frac{2}{x - 1} - \frac{1}{( x - 1 ) ^{2}})

\int \frac{1}{x ^{3} - 2 x ^{2} + x} d x = ln ∣ x ∣ - ln ∣ x - 1 ∣ - \frac{1}{x - 1}

= 4 (ln ∣ x - 1 ∣ - \frac{1}{x - 1}) - 9 (\frac{x}{x ^{2} - 2 x + 1} - \frac{2}{x - 1} - \frac{1}{( x - 1 ) ^{2}}) + ln ∣ x ∣ - ln ∣ x - 1 ∣ - \frac{1}{x - 1}

Vereinfache

4 (ln ∣ x - 1 ∣ - \frac{1}{x - 1}) - 9 (\frac{x}{x ^{2} - 2 x + 1} - \frac{2}{x - 1} - \frac{1}{( x - 1 ) ^{2}}) + ln ∣ x ∣ - ln ∣ x - 1 ∣ - \frac{1}{x - 1} : - \frac{9 x}{x ^{2} - 2 x + 1} + 3 ln ∣ x - 1 ∣ + \frac{13}{x - 1} + \frac{9}{( x - 1 ) ^{2}} + ln ∣ x ∣

= - \frac{9 x}{x ^{2} - 2 x + 1} + 3 ln ∣ x - 1 ∣ + \frac{13}{x - 1} + \frac{9}{( x - 1 ) ^{2}} + ln ∣ x ∣

Füge eine Konstante zur Lösung hinzu

= - \frac{9 x}{x ^{2} - 2 x + 1} + 3 ln ∣ x - 1 ∣ + \frac{13}{x - 1} + \frac{9}{( x - 1 ) ^{2}} + ln ∣ x ∣ + C

Graph

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