What is area y=x^2,y=sqrt(6+x) ?

The answer to area y=x^2,y=sqrt(6+x) is 5.12244…

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area y=x^2,y=sqrt(6+x)

area

y = x^{2}, y = 6 + x

5.12244 \dots

Solution steps

Apply the area formula:

\int_{- 1.45972 \dots}^{1.66384 \dots} x^{2} - 6 + x d x

Solve

\int_{- 1.45972 \dots}^{1.66384 \dots} x^{2} - 6 + x d x : 5.12244 \dots

The area is:

= 5.12244 \dots

\frac{d}{d x} (lo g_{e} (4 x))

\frac{d}{d x} ((8 (4 x)^{4} + 5)^{3})

\frac{\partial}{\partial y} (arctan (x) y)

4 - ln (x)

y^{^{''}} + 4 y^{^{'}} + 40 y = 40 cos (8 t)

What is area y=x^2,y=sqrt(6+x) ?
The answer to area y=x^2,y=sqrt(6+x) is 5.12244…